Apply Operations to an Array Python Solution

lcpy gen -n 2460   # by problem number
lcpy gen -s apply_operations_to_an_array   # by problem name

Input: nums = [1,2,2,1,1,0]
Output: [1,4,2,0,0,0]
Explanation: We do the following operations:
- i = 0: nums[0] and nums[1] are not equal, so we skip this operation.
- i = 1: nums[1] and nums[2] are equal, we multiply nums[1] by 2 and change nums[2] to 0. The array becomes [1,4,0,1,1,0].
- i = 2: nums[2] and nums[3] are not equal, so we skip this operation.
- i = 3: nums[3] and nums[4] are equal, we multiply nums[3] by 2 and change nums[4] to 0. The array becomes [1,4,0,2,0,0].
- i = 4: nums[4] and nums[5] are equal, we multiply nums[4] by 2 and change nums[5] to 0. The array becomes [1,4,0,2,0,0].
After that, we shift the 0's to the end, which gives the array [1,4,2,0,0,0].

Input: nums = [0,1]
Output: [1,0]
Explanation: No operation can be applied, we just shift the 0 to the end.

class Solution:
    # Time: O(n)
    # Space: O(1) extra, output written in place
    def apply_operations(self, nums: list[int]) -> list[int]:
        n = len(nums)
        for i in range(n - 1):
            if nums[i] == nums[i + 1]:
                nums[i] *= 2
                nums[i + 1] = 0
        insert = 0
        for read in range(n):
            if nums[read] != 0:
                nums[insert] = nums[read]
                insert += 1
        for idx in range(insert, n):
            nums[idx] = 0
        return nums