Count of Matches in Tournament Python Solution

lcpy gen -n 1688   # by problem number
lcpy gen -s count_of_matches_in_tournament   # by problem name

Input: n = 7
Output: 6
Explanation: Details of the tournament:
- 1st Round: Teams = 7, Matches = 3, and 4 teams advance.
- 2nd Round: Teams = 4, Matches = 2, and 2 teams advance.
- 3rd Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 3 + 2 + 1 = 6.

Input: n = 14
Output: 13
Explanation: Details of the tournament:
- 1st Round: Teams = 14, Matches = 7, and 7 teams advance.
- 2nd Round: Teams = 7, Matches = 3, and 4 teams advance.
- 3rd Round: Teams = 4, Matches = 2, and 2 teams advance.
- 4th Round: Teams = 2, Matches = 1, and 1 team is declared the winner.
Total number of matches = 7 + 3 + 2 + 1 = 13.

class Solution:
    # Time: O(1)
    # Space: O(1)
    def number_of_matches(self, n: int) -> int:
        # Each match eliminates exactly one team, and all but the winner are
        # eliminated, so n - 1 matches are played regardless of pairing rules.
        return n - 1