You are given the root of a full binary tree with the following properties:
Leaf nodes have either the value 0 or 1, where 0 represents False and 1 represents True.
Non-leaf nodes have either the value 2 or 3, where 2 represents the boolean OR and 3 represents the boolean AND.
The evaluation of a node is as follows:
If the node is a leaf node, the evaluation is the value of the node, i.e. True or False.
Otherwise, evaluate the node’s two children and apply the boolean operation of its value with the children’s evaluations.
Return the boolean result of evaluating therootnode.A full binary tree is a binary tree where each node has either 0 or 2 children.A leaf node is a node that has zero children.
Input: root = [2,1,3,null,null,0,1]Output: trueExplanation: The above diagram illustrates the evaluation process.The AND node evaluates to False AND True = False.The OR node evaluates to True OR False = True.The root node evaluates to True, so we return true.
Input: root = [0]Output: falseExplanation: The root node is a leaf node and it evaluates to false, so we return false.
from leetcode_py import TreeNodeclass Solution: # Time: O(n) # Space: O(h) def evaluate_tree(self, root: TreeNode[int] | None) -> bool: if root is None: return False if root.left is None and root.right is None: return root.val == 1 left = self.evaluate_tree(root.left) right = self.evaluate_tree(root.right) return (left or right) if root.val == 2 else (left and right)
