Least Number of Unique Integers after K

lcpy gen -n 1481   # by problem number
lcpy gen -s least_number_of_unique_integers_after_k_removals   # by problem name

Input: arr = [5,5,4], k = 1
Output: 1
Explanation: Remove the single 4, only 5 is left.

Input: arr = [4,3,1,1,3,3,2], k = 3
Output: 2
Explanation: Remove 4, 2 and either one of the two 1s or three 3s. 1 and 3 will be left.

from collections import Counter


class Solution:
    # Time: O(n log n)
    # Space: O(n)
    def find_least_num_of_unique_ints(self, arr: list[int], k: int) -> int:
        counts = sorted(Counter(arr).values())
        remaining = len(counts)
        for count in counts:
            if k < count:
                break
            k -= count
            remaining -= 1
        return remaining