LeetCode 1846, Medium. Topics: Array, Greedy, Sorting. View on LeetCode.
Generate this problem as a practice environment: tested reference solution, 18 parametrized pytest cases, and a playground notebook:
Problem
You are given an array of positive integers arr. Perform some operations (possibly none) on arr so that it satisfies these conditions:
- The value of the first element in
arr must be 1.
- The absolute difference between any 2 adjacent elements must be less than or equal to 1. In other words,
abs(arr[i] - arr[i - 1]) <= 1 for each i where 1 <= i < arr.length (0-indexed). abs(x) is the absolute value of x.
There are 2 types of operations that you can perform any number of times:
- Decrease the value of any element of
arr to a smaller positive integer.
- Rearrange the elements of
arr to be in any order.
Return the maximum possible value of an element in arr after performing the operations to satisfy the conditions.
Examples
Explanation: We can satisfy the conditions by rearranging arr so it becomes [1,2,2,2,1]. The largest element in arr is 2.
Explanation: Rearrange arr so it becomes [1,100,1000]. Decrease the second element to 2 and the third element to 3. Now arr = [1,2,3], which satisfies the conditions. The largest element in arr is 3.
Explanation: The array already satisfies the conditions, and the largest element is 5.
Constraints
- 1 <= arr.length <= 10^5
- 1 <= arr[i] <= 10^9
Solution
Reference implementation from solution.py on GitHub, full suite in test_solution.py:
Complexity
NeetCode All. Last modified on September 7, 2026