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LeetCode 268, Easy. Topics: Array, Hash Table, Math, Binary Search, Bit Manipulation, Sorting. View on LeetCode. Generate this problem as a practice environment: tested reference solution, 13 parametrized pytest cases, and a playground notebook:

Problem

Given an array nums containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array.

Examples

Explanation: n = 3 since there are 3 numbers, so all numbers are in the range [0,3]. 2 is the missing number in the range since it does not appear in nums.
Explanation: n = 2 since there are 2 numbers, so all numbers are in the range [0,2]. 2 is the missing number in the range since it does not appear in nums.
Explanation: n = 9 since there are 9 numbers, so all numbers are in the range [0,9]. 8 is the missing number in the range since it does not appear in nums.

Constraints

  • n == nums.length
  • 1 <= n <= 10^4
  • 0 <= nums[i] <= n
  • All the numbers of nums are unique.
Follow up: Could you implement a solution using only O(1) extra space complexity and O(n) runtime complexity?

Solution

Reference implementation from solution.py on GitHub, full suite in test_solution.py:

Complexity

Tags

Grind, Blind 75, NeetCode 150, NeetCode 250, NeetCode All.
Last modified on August 25, 2026