Number of Recent Calls Python Solution

lcpy gen -n 933   # by problem number
lcpy gen -s number_of_recent_calls   # by problem name

Input
["RecentCounter", "ping", "ping", "ping", "ping"]
[[], [1], [100], [3001], [3002]]
Output
[null, 1, 2, 3, 3]

Explanation
RecentCounter recentCounter = new RecentCounter();
recentCounter.ping(1); // requests = [1], range is [-2999,1], return 1
recentCounter.ping(100); // requests = [1, 100], range is [-2900,100], return 2
recentCounter.ping(3001); // requests = [1, 100, 3001], range is [1,3001], return 3
recentCounter.ping(3002); // requests = [1, 100, 3001, 3002], range is [2,3002], return 3

from collections import deque


class RecentCounter:
    # Time: O(1) amortized per ping call
    # Space: O(W) where W is the number of requests in the current 3000ms window
    def __init__(self) -> None:
        self.requests: deque[int] = deque()

    # Time: O(1) amortized (each timestamp is appended and popped at most once)
    # Space: O(1) beyond the stored window
    def ping(self, t: int) -> int:
        self.requests.append(t)
        while self.requests[0] < t - 3000:
            self.requests.popleft()
        return len(self.requests)