Reorder Data in Log Files Python Solution

lcpy gen -n 937   # by problem number
lcpy gen -s reorder_log_files   # by problem name

Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
Explanation:
The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".

Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]

class Solution:
    # Time: O(n * m log n) where n = len(logs), m = max log length
    # Space: O(n * m)
    def reorder_log_files(self, logs: list[str]) -> list[str]:
        letters: list[str] = []
        digits: list[str] = []
        for log in logs:
            rest = log.split(" ", 1)[1]
            if rest[0].isdigit():
                digits.append(log)
            else:
                letters.append(log)
        letters.sort(key=lambda log: (log.split(" ", 1)[1], log.split(" ", 1)[0]))
        return letters + digits