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LeetCode 15, Medium. Topics: Array, Two Pointers, Sorting. View on LeetCode. Generate this problem as a practice environment: tested reference solution, 12 parametrized pytest cases, and a playground notebook:

Problem

Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. Notice that the solution set must not contain duplicate triplets.

Examples

Explanation: nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0. nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0. nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0. The distinct triplets are [-1,0,1] and [-1,-1,2]. Notice that the order of the output and the order of the triplets does not matter.
Explanation: The only possible triplet does not sum up to 0.
Explanation: The only possible triplet sums up to 0.

Constraints

  • 3 <= nums.length <= 3000
  • -10^5 <= nums[i] <= 10^5

Solution

Reference implementation from solution.py on GitHub, full suite in test_solution.py:

Complexity

Tags

Grind 75, Grind, Blind 75, NeetCode 150, NeetCode 250, NeetCode All, AlgoMaster 75.
Last modified on August 25, 2026