LeetCode 15, Medium. Topics: Array, Two Pointers, Sorting. View on LeetCode.
Generate this problem as a practice environment: tested reference solution, 12 parametrized pytest cases, and a playground notebook:
Problem
Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0.
Notice that the solution set must not contain duplicate triplets.
Examples
Explanation:
nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0.
nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0.
nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0.
The distinct triplets are [-1,0,1] and [-1,-1,2].
Notice that the order of the output and the order of the triplets does not matter.
Explanation: The only possible triplet does not sum up to 0.
Explanation: The only possible triplet sums up to 0.
Constraints
- 3 <= nums.length <= 3000
- -10^5 <= nums[i] <= 10^5
Solution
Reference implementation from solution.py on GitHub, full suite in test_solution.py:
Complexity
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